0,6x+9x^2=0

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Solution for 0,6x+9x^2=0 equation: 



0.6x+9x^2=0

a = 9; b = 0.6; c = 0;
Δ = b2-4ac
Δ = 0.62-4·9·0
Δ = 0.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.6)-\sqrt{0.36}}{2*9}=\frac{-0.6-\sqrt{0.36}}{18}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.6)+\sqrt{0.36}}{2*9}=\frac{-0.6+\sqrt{0.36}}{18}
$

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